Tuesday
09Jan2007
C++/CLI: Explicitly Implement Interface Properties
Tuesday, January 9, 2007 at 21:37 In case you ever wondered how to explicitly implement interface properties in C++/CLI that collide with an already existing better typed property: It’s quite easy, but I didn’t find a sample in neither the language specification nor the web.
Imagine you have some already existing generic ItemBuilder class:
ref class Item;
generic<class T>
where T : Item
public ref class ItemBuilder
{
public:
property T Prototype { T get(); };
};
generic<class T>
where T : Item
public ref class ItemBuilder
{
public:
property T Prototype { T get(); };
};
But now you want to generalize it, to be able to access the prototype property as Item, independent of the actual generic class type. So you define an interface IItemBuilder:
public interface class IItemBuilder
{
property Item^ Prototype { Item^ get(); };
};
{
property Item^ Prototype { Item^ get(); };
};
How to explicitly implement this interface in ItemBuilder in C++/CLI?
generic<class T>
where T : Item
public ref class ItemBuilder : public IPacketBuilder
{
private:
virtual property Item^ PrototypeUntyped
{ Item^ get() sealed = IItemBuilder::Prototype::get; };
public:
property T Prototype { T get(); };
};
where T : Item
public ref class ItemBuilder : public IPacketBuilder
{
private:
virtual property Item^ PrototypeUntyped
{ Item^ get() sealed = IItemBuilder::Prototype::get; };
public:
property T Prototype { T get(); };
};
Let me know if you know a better approach …
tagged .Net, C++/CLI in Programming
.Net, C++/CLI in Programming 
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